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7n^2+42-112=0
We add all the numbers together, and all the variables
7n^2-70=0
a = 7; b = 0; c = -70;
Δ = b2-4ac
Δ = 02-4·7·(-70)
Δ = 1960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1960}=\sqrt{196*10}=\sqrt{196}*\sqrt{10}=14\sqrt{10}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{10}}{2*7}=\frac{0-14\sqrt{10}}{14} =-\frac{14\sqrt{10}}{14} =-\sqrt{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{10}}{2*7}=\frac{0+14\sqrt{10}}{14} =\frac{14\sqrt{10}}{14} =\sqrt{10} $
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